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Comparing large numbers Write a program to check whether a given relation is true for a given pair of numbers.

Input You are provided with an unknown number of test cases. Each test case consists of a natural number, which is followed by a white space, relational operator (==, !=, >= or <=), white space, and another natural number. All test cases are separated by a new line character. You can assume that no number has more than 1000 digits. Output A binary sequence should appear as the output. ith element of the sequence should be equal to 1 or 0, depending on whether the corresponding relation is true or false. All elements of the sequence should be separated with a new line character. Examples: Input : 100 == 200 200 <= 100 200 != 100 Output : 0 0 1 contents = [] variable = [] i=0 while True: try: line = raw_input("") except EOFError: break contents.append(line) for val in contents: variable = contents[i].split(" ") if variable[1]== '==': if int(variable[0]) == int(variable[2]): print 2-1 ...

Write a program to insert an element in the particular position in a given Linkedlist TCS Question

Input In the first line, there are two integer numbers (X and P) will be given. First number(X) is the element to be inserted into the linked list, Second number(P) is the position where the element X to be inserted in the linkedlist. In second line, You are provided with a set of integer elements as a linkedlist (Ni, i is 0,1,…n) followed by white spaces and ends with NULL indicates end of linkedlist. Output You have to print the new linkedlist elements after the insertion Examples: Input : 3 0 1 2 NULL Output : 3 1 2 NULL // Java program to insert an element in the particular position in a given Linkedlist import java.util.Scanner; class LinkedList { Node head; // head of list /* Linked list Node*/ class Node { int data; Node next; Node(int d) { data = d; next = null; } } /* Inserts a new Node at front of the list. */ public void push(int new_data) { /* 1 ...

Killjee and easy problem

Killjee is solving an easy problem. Given an array  a a  containing  N N  positive integers. You need to find the magic value of the array. Magic value of an array is  ∑ N i = 1 ( b i i ) ∑ i = 1 N ( b i i ) . where,  b i b i  is number of set bits of  a i a i . Find and print the answer  Modulo   ( 10 10 + 11 ) ( 10 10 + 11 ) INPUT CONSTRAINTS 1 ≤ N ≤ 10 5 1 ≤ N ≤ 10 5 1 ≤ a i ≤ 10 9 1 ≤ a i ≤ 10 9 INPUT FORMAT First line of input contains a single integer  N N . Next line contains  N N  space separated integers, elements of array  a a . OUTPUT FORMAT Output a single integer, magic value of the array. Sample Input 3 1 2 4 Sample Output 3 Explanation b [ 1 ] = 1 , b [ 2 ] = 1 b [ 1 ] = 1 , b [ 2 ] = 1  and  b [ 3 ] = 1 b [ 3 ] = 1  so, summation of  b [ i ] i b [ i ] i  =  1 + 1 + 1 = 3 1 + 1 + 1 = 3 . Note:  Your code should be able to c...

Plus Minus C and Java Solution

Problem: Given an array of integers, calculate which fraction of its elements are  positive , which fraction of its elements are  negative , and which fraction of its elements are  zeroes , respectively. Print the decimal value of each fraction on a new line. Note:  This challenge introduces precision problems. The test cases are scaled to six decimal places, though answers with absolute error of up to   are acceptable. Input Format The first line contains an integer,  , denoting the size of the array.  The second line contains   space-separated integers describing an array of numbers  . Output Format You must print the following   lines: A decimal representing of the fraction of  positive  numbers in the array. A decimal representing of the fraction of  negative  numbers in the array. A decimal representing of the fraction of  zeroes  in the array. ...