Comparing large numbers Write a program to check whether a given relation is true for a given pair of numbers.

Input
You are provided with an unknown number of test cases. Each test case consists of a natural number, which is followed by a white space, relational operator (==, !=, >= or <=), white space, and another natural number. All test cases are separated by a new line character. You can assume that no number has more than 1000 digits.

Output
A binary sequence should appear as the output. ith element of the sequence should be equal to 1 or 0, depending on whether the corresponding relation is true or false. All elements of the sequence should be separated with a new line character.

Examples:

Input :
100 == 200
200 <= 100
200 != 100

Output :
0
0
1

contents = []
variable = []
i=0
while True:
    try:
        line = raw_input("")
    except EOFError:
        break
    contents.append(line)
for val in contents:
    variable = contents[i].split(" ")
    if variable[1]== '==':
        if int(variable[0]) == int(variable[2]):
            print 2-1
        else:
            print 1-1
    elif variable[1] == '!=':
        if int(variable[0]) != int(variable[2]):
            print 2-1
        else:
            print 1-1
    elif variable[1] == '>=':
        if int(variable[0]) >= int(variable[2]):
            print 2-1
        else:
            print 1-1
    elif variable[1] == '<=':
        if int(variable[0]) <= int(variable[2]):
            print 2-1
        else:
            print 1-1
    i+=1