Problem:
Given a square matrix of size , calculate the absolute difference between the sums of its diagonals.
Input Format
The first line contains a single integer, . The next lines denote the matrix's rows, with each line containing space-separated integers describing the columns.
Output Format
Print the absolute difference between the two sums of the matrix's diagonals as a single integer.
Sample Input
3
11 2 4
4 5 6
10 8 -12
Sample Output
15
Explanation
The primary diagonal is:
11
5
-12
11
5
-12
Sum across the primary diagonal: 11 + 5 - 12 = 4
The secondary diagonal is:
4
5
10
Sum across the secondary diagonal: 4 + 5 + 10 = 19
Difference: |4 - 19| = 15
4
5
10
Sum across the secondary diagonal: 4 + 5 + 10 = 19
Difference: |4 - 19| = 15
Solution:
// C Solution
int main()
{
int a[100][100],n,c=0,d=0,i,j,sum=0;
scanf("%d",&n);
for(i=0;i
// Java Solution
import java.io.*;
import java.util.*;
public class VeryBigSum {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
sc.nextLine();
String[]numArray = sc.nextLine().split(" ");
long sum = 0;
for(String num:numArray){
if(!num.equals("")){
sum+=Long.parseLong(num);
}
}
System.out.println(sum);
}
}
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